Question

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PLZZZ SOLVE IT .....❤️❤️

Answer 1

Let the atomic weight of alkali metal A be x. When it reacts with water, it forms a compound B having molecular mass 40. Let the reaction be

2A+2H20----> 2AOH+H2 (B)

According to the question,

x + 16 + 1 = 40 (Given)

x = 40-17 = 23

It is the atomic weight of Na (sodium).  

Therefore, the alkali metal A is sodium (Na) and the reaction is

2Na+2H20----> 2NaOH+h2

So, compound B is sodium hydroxide (NaOH).  

Sodium hydroxide reacts with aluminium oxide (Al2O3) to give sodium aluminate (NaAlO2). Thus, C is sodium aluminate (NaAlO2). The reaction involved is Al2O3+

 

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