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Prove that :-
tan8α - tan5α - tan3α = tan8α tan5α tan3α
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28
It is the study of angles and the relationships between the angles and ratios sine, cosine, tangent, cosectant, sectant, cotangent.
Ashishkumar098:
ohh ohh Thanks bhaiya :)
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1
tan8A = tan(3A + 5A )
tan8A = tan3A + tan5A /1 - tan3A×tan5A
✓using formula tan(A+B) = tanA+tanB/1 - tanA×tanB
hence,
tan8A(1 - tan3A×tan5A) = tan3A + tan5A
tan8A - tan3A×tan5A×tan8A = tan3A+tan5A
tan3A - tan3A - tan5A =tan3A*tan5A*tan8A
[REARRANGING TERM]
Hence here Prooved
tan8A - tan3A - tan5A = tan3A*tan5A*tan8A
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