Math, asked by nive890, 9 months ago

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Question -
2sin (theta) + 3tan (theta) = ?



Answers

Answered by pournimadaphal
0

Answer:

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Answered by jitumahi435
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2\sin \theta + 3\tan \theta = \tan \theta (2\cos \theta+3)

Step-by-step explanation:

We have,

2\sin \theta + 3\tan \theta

To find, 2\sin \theta + 3\tan \theta = ?

2\sin \theta + 3\tan \theta

Using the trigonometric identity,

\tan A=\dfrac{\sin A}{\cos A}

= 2\sin \theta+  3\dfrac{\sin \theta}{\cos \theta}

Taking LCM of denominator part, we get

= \dfrac{2\sin \theta\cos \theta+3\sin \theta}{\cos \theta}

Taking \sin \theta as common in denominator, we get

= \dfrac{\sin \theta(2\cos \theta+3)}{\cos \theta}

= \dfrac{\sin \theta}{\cos \theta} (2\cos \theta+3)

= \tan \theta (2\cos \theta+3)

∴ 2\sin \theta + 3\tan \theta = \tan \theta (2\cos \theta+3)

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