Question

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Question:- A solid cylinder of mass 20kg rotates about its axis with angular speed 100rad/s ,the radius of the cylinder is 0.25m . What is the magnitude of the angular momentum of the cylinder about its axis .


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Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Angular\: Momentum (L)=62.5\:j.s}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Mass of solid cylinder (m) =20kg

• Angular speed ($\sf{\omega}$)=100rad/s

• Radius of cylinder (R)=0.25m

$\large\underline\pink{\sf To\:Find: }$

• Magnitude of Angular Momentum (L) = ?

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We know

Momentum of Inertia of the cylinder about its axis .

$\large{\boxed{\sf I=\frac{1}{2}MR^2}}$

$\large\implies{\sf I=\frac{1}{2}×20×(0.25)^2}$

$\large\implies{\sf I=0.625\:kg-m^2 }$

Angular Momentum (L) :

$\large{\boxed{\sf L=I\omega}}$

$\large\implies{\sf L=0.625×100}$

$\large\implies{\sf L=62.5\:joule-second}$

$\large\red{\boxed{\sf Angular\: Momentum (L)=62.5\:j.s}}$

Answer 2

see the attached image for ur answer