HEYA !!
QUESTION :
If force, velocity and time are taken as fundamental quantities.
What would be dimension of work.
Answers
Answered by
4
Force = m×a
m = mass
a = acceleration
W = F× S. ------------------- (I)
S= displacement
Change of rate with respect time and velocity
V = S / t
S = V × t
from equation (I)
[ W = F ×V × t ] N×m
W = work ( Jule)
F = Force ( Nuton)
V = Velocity ( m/sec)
t = Time. (sec)
this formula, dimension formula of the work when force, time and velocity are taken as fundamental quantities.
================
I hope it's help you....!! :) ✌️✌️
m = mass
a = acceleration
W = F× S. ------------------- (I)
S= displacement
Change of rate with respect time and velocity
V = S / t
S = V × t
from equation (I)
[ W = F ×V × t ] N×m
W = work ( Jule)
F = Force ( Nuton)
V = Velocity ( m/sec)
t = Time. (sec)
this formula, dimension formula of the work when force, time and velocity are taken as fundamental quantities.
================
I hope it's help you....!! :) ✌️✌️
GauravSaxena01:
yes i know
Answered by
5
Thanks for your question !
Work will be force and displacement's product. Thus, W = F × s. Where, W is work, F is force and s is displacement done.
We know that, v = s/t. *(above units will be as it is including v = velocity and t = time)
Therefore the distance has its dimensions. Where, we come to know important units are - time × velocity. That is, t × v.
Hence, the answer is - Dimensions of work done here are F v t. Where, F is force. v is velocity and t is time.
Work will be force and displacement's product. Thus, W = F × s. Where, W is work, F is force and s is displacement done.
We know that, v = s/t. *(above units will be as it is including v = velocity and t = time)
Therefore the distance has its dimensions. Where, we come to know important units are - time × velocity. That is, t × v.
Hence, the answer is - Dimensions of work done here are F v t. Where, F is force. v is velocity and t is time.
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