Physics, asked by Anonymous, 1 year ago

HEYA !!

QUESTION :

If force, velocity and time are taken as fundamental quantities.

What would be dimension of work.

Answers

Answered by GauravSaxena01
4
Force = m×a

m = mass
a = acceleration

W = F× S. ------------------- (I)
S= displacement

Change of rate with respect time and velocity

V = S / t
S = V × t

from equation (I)

[ W = F ×V × t ] N×m

W = work ( Jule)
F = Force ( Nuton)
V = Velocity ( m/sec)
t = Time. (sec)

this formula, dimension formula of the work when force, time and velocity are taken as fundamental quantities.

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I hope it's help you....!! :) ✌️✌️

GauravSaxena01: yes i know
GauravSaxena01: me add karta hu
Anonymous: answer it with that
Anonymous: oky thanks
GauravSaxena01: ok
GauravSaxena01: thanks but me spelling correction nahi kar skta dear
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Anonymous: thanks for ur answer :)
Answered by no4
5
Thanks for your question !

        Work will be force and displacement's product. Thus, W = F × s. Where, W is work, F is force and s is displacement done.

        We know that, v = s/t. *(above units will be as it is including v = velocity and t = time)

        Therefore the distance has its dimensions.  Where, we come to know important units are - time × velocity. That is, t × v.

        Hence, the answer is - Dimensions of work done here are F v t. Where, F is force. v is velocity and t is time.

Anonymous: thanks sir :)
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