Question

HEYA !
Question -: In the attachment. .

Q4

Answer 1

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⭐ Given, the diagonal of rectangle = 26 cm.
⭐ If we divide it equally we get (13+13) cm = 26 cm.
⭐ We had taken BD = 26 cm.
AB = 24 cm.

⭐ By applying pythagoras theorem in the right angled triangle ABD, we get, AD (other side)
= $\sqrt{ {26}^{2} - {24}^{2} }$
$= \sqrt{676 - 576}$
$= \sqrt{100}\:cm$
$= 10\:cm$

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Answer 2

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$In \: triangle \: ABC, \\ \\ </h2><h2></h2><h2>By \: pythagoras \: theorem, \\ {h}^{2} = {p}^{2} + {b}^{2} \\ {26}^{2} = {x }^{2} + {24}^{2} \\ 676 = {x}^{2} + 576 \\ {x}^{2} = 676 - 576 \\ x = \sqrt{100} \\x = 10cm$

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