Heya !!
⚫ Question :-
⚫ Prove Apolloneous Theorem.
⚫ Class :- 10th
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Heya!!
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Apollonius Theorem :
The sum of squares of any two side of a triangle equals twice the square of half the third side, together with twice square of the median which bisects the third side.
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If ABC is a triangle and AD(median) bisects the third side BC then BD = CD.
Construction : Draw AE perpendicular to BC.
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To proof : AB^2 + AC^2 = 2(BD^2 + AD^2)
------------------------------
Hope it helps u :)
--------------------------
Apollonius Theorem :
The sum of squares of any two side of a triangle equals twice the square of half the third side, together with twice square of the median which bisects the third side.
--------------------------------
If ABC is a triangle and AD(median) bisects the third side BC then BD = CD.
Construction : Draw AE perpendicular to BC.
------------------------------
To proof : AB^2 + AC^2 = 2(BD^2 + AD^2)
------------------------------
Hope it helps u :)
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