Question

Heya !!


Refer to the attachment above for answer.



Thanks !

Answer 1

$\mathcal{\huge{\underline{\underline{\star\:Hey\:Mate\:\star}}}}$

$\textbf{Solution:}$

Given :

Initial velocity = 10 km/h

=> 10 × 5/18

=> 50 / 18

=> 25 / 9 m/s


Final Velocity = 15 km/h

=> 15 × 5 / 18

=> 75 / 18 -- m/s

=> 25 / 6

Time taken = 6 second.

Using First equation of motion..

v = u + at

=> 25/6 = 25/9 + a × 6

=> 25 / 6 - 25/9 = 6a

=> 75 - 50 / 18 = 6a

=> 25 = 108 a

=> a = 25 / 108

=> a = 0.22 m/s

=> a = 0.22 m/s²

____________________

Thanks for the question !

Answer 2

we know that the acceleration is equal to the change in velocity with respect to time.
so, here v1 and v2 are 10km/h and 15km/h
time taken 6 sec
so at first we need to convert kilometres and hours into metres and seconds.
v1 =
$10 \times \frac{1000}{60×60}$
v2=
$15 \times \frac{1000}{60×60}$

therefore we get new values of v1 and v2 are 2.78m/sec and 4.17 m/sec respectively.
now using acceleration formula
$a = \frac{v2 - v1}{time \: taken}$
a = (4.17-2.78)/6

hence the acceleration is 0.23 m/s^2
hope you got it :)