HEYA...... RYTHME HERE
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#NEED FULL EXPLANATION
#10 POINTS
#NOSPAMS
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Hint :
(i) 2^10 ends in 24.
(ii) 24 raised to even powers ends in 76 and 24 raised to odd powers ends in 24.
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Given : (2)^999
= > (2^10)^99 * (2)^9
= > (24)^99 * (2)^9
= > 24 * 512
= > 12288.
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Therefore, the last two digits of (2)^999 = 88.
Hope this helps!
siddhartharao77:
:-)
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