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solve question 12
X No sPam X
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flocculating value we have to find
its in 1 litre of sol minimum millimoles of electrolyte needed
for 200 ml its 0.73 g = 0.73× 10^3/1+35.5 = 0.73× 10^3/36.5 = 20
in 1 L its 5 times = 100
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