Question

Heya❗️❗️

Solve this✌️✌️

Answer 1

here is your answer i hope this is helpful for you

Answer 2

HELLO DEAR,

$\bold{\int{\frac{e^{tan^{-1}x}}{1 + x^2}}\,dx}$

let tan^{-1}x = t
⇒1/(1 + x²) = dt/dx
⇒dx = (1 + x²).dt

so, $\bold{\int{\frac{e^{tan^{-1}x}}{1 + x^2}*(1 + x^2)}\,dt}$

⇒$\bold{\int{e^t}\,dt}$

⇒e^t + c
put the value of t in above function

⇒$\bold{e^{tan^{-1}x} + c}$

I HOPE ITS HELP YOU DEAR,
THANKS