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B/√2/B @=1/√2 that is perpendicular/hypotenuse=sin theta
sin theta =1/√2... there fore theta =45°
sin theta =1/√2... there fore theta =45°
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Answered by
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Hyy dear
here is your answer
Sin thetha =P/H
then,
sin thetha = R/B
= B/√2 /B
= 1/√2
sin thetha = sin 45°
thetha = 45°
hope its help u
mark as brainlist
here is your answer
Sin thetha =P/H
then,
sin thetha = R/B
= B/√2 /B
= 1/√2
sin thetha = sin 45°
thetha = 45°
hope its help u
mark as brainlist
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