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The base of a right triangle ABC is 48 cm and its hypotenuse is 50 cm long. Then, find the area of the triangle ?
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Answers
Answer:
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cute here is your answer
Question:-the base of a right triangle is 48 cm and its hypotenuse is 50 cm long. the area of the triangle is?
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Solution:-)
GIVEN THAT - Base of Right∆ =48
Also given- Hypotenuse of Right∆=50
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Hypotenuse² =Base² + Height²
(50)² = (48)² + Height²
2500 - 2304 = Height²
196 = Height²
14cm = Height
48cm = Base
50cm = Height
Area of a triangle = 1/2 bh
1/2 * 48 * 14
= 336cm²
Step-by-step explanation:
hope it will help you
Answer:
Area = 336 cm^2
Step-by-step explanation:
Given :
Right angled triangle ABC with ->
Base (BC) = 48 cm
hypotenuse (AC) = 50 cm
To Find :
Area ?
Solution :
AC^2 = AB^2 + BC^2
AB^2 = AC^2 - BC^2
= (50)^2 - (48)^2
= 2500 - 2304
= 196
AB = √196
= 14
Hence , Height (AB) = 14 cm
Now ,
Area of a right angled triangle =>
= 1/2 x ( Base x corresponding height )
= 1/2 x ( 48 x 14 )
= 672 / 2
= 336 cm^2
Therefore , the area of the triangle is 336 cm ^2.
hope it helps you