Question

HEYA ⛈ ⛈
The " Gravity"

Answer 1

$\huge\boxed{\texttt{\fcolorbox{aqua}{red}{BONJOUR\: FRIEND}}}$
$\bf{\purple{\mathfrak{\underline{HERE'S\: THE\: ANSWER}}}}$
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$g_{h} = \frac{1}{16} \: or$

or

GM/(R+h)^2=1/16 GM/R^2

R+h=4R

h=4R-R

h=3R ANSWER

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Answer 2

Answer:

h =3r

option no 1

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