Question

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Q1 Two brands of chocolates are available in packs of 24 and 15 respectively. If need to buy an equal number of chocolates of both kinds, what is the least number of boxes of each kind i would need to buy?


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Class 10th, extra question from ch-1

Answer 1

finding this means to find the lcm of both


24 = 2 × 2 × 2 × 3

15 = 3 × 5


lcm = 2 × 2 × 2 × 3 × 5

= 120


therefore 5 boxes of 24

and

8 boxes of 15

Answer 2

Hey friend

here is your answer

as given there are two packs of chocolates, each having different fixed amount of chocolates i.e. 24 and 15.

if you want to buy same no. of chocolates,
you must have to know how packs of each box are to be bought.

to find how much packs of each kind are required, we have to find the L.C.M. of both no. of chocolates in each pack

so, here we go......

$24 = 3 \times 2 \times 2 \times 2 \\ and \\ 15 = 3 \times 5 \\ \\ \\ therefore \: the \: lcm \: must \: be \: 120.$


now, as the L.C.M = 120
it means that 120 is the least no. of equilibrium of the chocolate of each packs.

so,

we have to buy 5 ( 120/24 ) packs of the packet which contains 24 chocolates each; and
we have to buy 8 ( 120/15 ) packs of the packet which contains 15 chocolates each.

glad to help you
hope it helps
thank you.