Question

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Q1 Two brands of chocolates are available in packs of 24 and 15 respectively. If need to buy an equal number of chocolates of both kinds, what is the least number of boxes of each kind I would need to buy?
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Answer 1

Heya!!
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♦Two brands of Chocolates are available in packs of 24 and 15 respectively. If I need to buy an equal number of Chocolates of both Kinds , what is the least number of boxes of each kind I need to buy ?



◾We need to Find the LCM [ Lowest Common Multiple ] of 24 and 15 first !!



⭐24 = 2 × 2 × 2 × 3

⭐15 = 3 × 5


✔LCM ( 15 , 24 ) => 120
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➰Number of Packs ➰
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♦120/24 = 5

♦120/15 = 8


◾⭐Hence he needs to buy 5 and 8 boxes of each kind respectively!!


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Answer 2

Heya

Here's your answer

As given there are two packs of chocolates, each having different fixed amount of chocolates i.e. 24 and 15.

if you want to buy same no. of chocolates, you must have to know how packs of each box are to bought.

to find how much packs of each kind are required, we have to find the L.C.M. of both no.of chocolates in each pack.

so, have we go............

24 = 3×2×2×2
and
15 = 3×5

$there \: fore \: the \: lcm \: must \: be \: 120.$

now, as the L.C.M. = 120
it means that 120 is the least no. of equilibrium of the chocolates of each packs.


so,
we have to buy 5(120/24) packs of the packet which contains 24 chocolates each;

and
we have to buy 8(120/15) packs of the packet which contains 15 chocolates each.

glad help you
it helps you
thank you,

@vaibhavhoax
# born with attitude