Question

Heya...!!!!!!!

Two objects, each of mass 8.8 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 6m s-² before the collision during which they stick together. ...What will be the velocity of the combined object after collision????

Note :-

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Question from NTSE ...
Asked by Shivam....​

Answer 1

Answer:

Given that

Mass of one of the objects,m1 = 1.5 kg

Mass of the other object, m2 = 1.5 kg

Velocity of m1 before collision, u1 = 2.5 m/s

Velocity of m2, moving in opposite direction before collision, u2 = -2.5 m/s

Find out

The velocity of the combined object after collision

Solution

Let v be the velocity of the combined object after the collision. By the law of conservation of momentum,

Total momentum after collision = Total momentum before collision,

Or, (m1 + m2) v = m1u1 + m2u2

Or, (1.5 + 1.5) v = 1.5 (2.5) + 1.5 (-2.5) [negative sign as moving in opposite direction]

Or, v = 0

Thus, the velocity of the combined object after the collision is 0 m/s

Answer

The velocity of the combined object after the collision is 0 m/s

Answer 2

Given :-

Two objects, each of mass 8.8 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 6m s-²

To Find :-

What will be the velocity of the combined object after collision?

Solution :-

Here,

m₁ = m₂

And

u₁ = 6 m/s

u₂ = -6 m/s

Now

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(8.8)(6) + (8.8)(-6) = 8.8v₁ + 8.8v₂

52.8 + (-52.8) = 17.6v₁

52.8 - 52.8 = 17.6v₁

0 = 17.6v₁

Therefore

The velocity is 0