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If the area of a rhombus be 24 cm² and one of its diagonals be 4 cm, find the perimeter of the rhombus.
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Area of rhombus = 24 cm square
one of its diagonal = 4 cm
let its other diagonal be X
so , 1/2 * 4 * X = 24cm square
x = 12 cm
we know that the diagonals of a rhombus bisect each other at eight angle .
now from one of the right triangle within it we will calculate the side of the rhombus .
the one of the side we get from above process = ( 36 + 4 ) ^ 1/ 2 = 40 ^ 1/2 = 2√ 10
so perimeter of the given rhombus = 4 * 22√10
= 82√ 10
one of its diagonal = 4 cm
let its other diagonal be X
so , 1/2 * 4 * X = 24cm square
x = 12 cm
we know that the diagonals of a rhombus bisect each other at eight angle .
now from one of the right triangle within it we will calculate the side of the rhombus .
the one of the side we get from above process = ( 36 + 4 ) ^ 1/ 2 = 40 ^ 1/2 = 2√ 10
so perimeter of the given rhombus = 4 * 22√10
= 82√ 10
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