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The length of the rectangle is 3 more twice the breadth of rectangle. if the length is reduced by 5 units and breadth increased by 3 units the area remains same. find the dimensions of the original rectangle and also the area.
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LEGENDARYSUMIT01:
length is 2b or 26 u have written
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HEY THERE!!!
Question:
The length of the rectangle is 3 more twice the breadth of rectangle. if the length is reduced by 5 units and breadth increased by 3 units the area remains same. find the dimensions of the original rectangle and also the area.
Solution:-
Let the breadth be x Centimeters
Then,
The length will be= x+3 Centimeters
Area of the rectangle = x(x+3) cm² --(A)
According to the Question;-
Given :-
length is increased by 9cm = x + 3 + 9 = x + 12 cm.
Given:-
Breadth is reduced by 5cm =) x - 5 cm.
Area of the rectangle = (x+12)(x-5). --- (2)
solving Equation by (1) and (2)So,we get Value
x(x+3) = (x+12)(x-5)
x²+ 3x = x² + 7x - 60
4x = 60
x = 15.
Breadth = 15cm.
Length = 15 + 3 = 18 cm.
Hence, Area of Rectangle= 18×15=270cm²
Thank you!!!
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