Question

Heya Users_____________❤❤
Solve question in attachment
Thanks☺

Answer 1

$\bold{Answer :}$

Let us take

z = a + b cosx

∴ dz = - b sinx dx

or, sinx dx = - (dz)/b

∴ ∫ (a + b cosx)ⁿ sinx dx

= ∫ zⁿ {- (dz)/b}

= - 1/b ∫ zⁿ dz

= - 1/b (zⁿ⁺¹)/(n + 1) + c, where c is integral constant and n ± (- 1)

= - 1/{b (n + 1)} (a + b cosx)ⁿ⁺¹ + c

#$\bold{MarkAsBrainliest}$

Answer 2

Answer:

Step-by-step explanation:

Attachment is given for reference