Question

HEYA!❤️❤️
What's up GUYZ ....
QUESTION----
AN ELECTRIC GEYSER CONSUMES 2.2 KILOWATT OF ELECTRICAL ENERGY PER HOUR OF ITS USE IT IS DESIGNED TO WORK ON THE MAINS VOLTAGE OF 220 VOLT
(A) WHAT IS THE POWER OF THIS DEVICE
(B)WHAT IS THE CURRENT FLOWING THROUGH THIS DEVICE
(B) WHAT IS THE RESISTANCE OF THIS DEVICE
(C) COST OF ENERGY CONSUMED IF EACH UNIT COSTS RUPEES 6.....​

Answer 1

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

V = 220 V E = 2.2 KWH as 1 unit = 1 KWH

Power = Energy/Time = 2.2 KWH / 1 hr =2.2 KW

I = P / V = 2.2 KW / 220V = 10 A

R = V / I = 22 Ω

==========================

Power P = V²/R => R = V² / P

100W ,220V lamp => R = 220²/100 Ohms

10 W , 220V night lamp => R = 220²/10 ohms

So the night lamp has higher resistance.

ᴍʀ ꜱʜᴀʀᴇᴇꜰ(｡♥‿♥｡)

Answer 2

Answer:

Hey mate

V = 220 V            

      E = 2.2 KWH     as 1 unit = 1 KWHPower = Energy/Time = 2.2 KWH / 1 hr  =2.2 KWI = P / V = 2.2 KW / 220V = 10 AR = V / I = 22 Ω

==========================

Power P = V²/R

   => R = V² / P

   => R = V² / P100W ,220V  lamp

 =>  R = 220²/100  Ohms

 =>  R = 220²/100  Ohms10 W , 220V  night lamp

=>  R = 220²/10  ohms

Hope it will be helpful to you

Thanks ☺️ ♥️ ✌️