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Write everything about Potentiometer u know
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☆ Hey friend ☆
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Here is your answer----------
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Potetiometer :--
============
It is a device which is used to measure the EMF of cell, comparing the EMF of two cells and to measure the internal resistance of a cell.
☆Principle of
============
Potentiometer :--
=============
Whenever a steady current flows through a wire of uniform area of cross-section and then the potential drop across the wire is directly proportional to the length of the wire.
☆ v is directly proportional to l
v=kl
k = v/l [ Potential gradient]
SI unit of it's is Volt/meter
☆Formula for determining the EMF of cell:--
E= vl'/l
Here, E is EMF of cell
l' is length on potentiometer wire at which galvanometer show null deflection.
l is the length of potentiometer wire
☆ Formula for comparing the EMF of two cells:--
E1 /E2 = l1/ l2
Here E1 = EMF of first cell
E2 = EMF of second cell
l1 = length on potentiometer at which first cell's null deflection is shown
l2 = length on potentiometer at which second cell's null deflection is shown
☆ Formula for determining Internal resistance of cell:--
r = [l1 - l2]/ l2 × R
r = internal resistance
R = Resistance selected by resistance box
Hope it will help you!
==================
Thanks!
=======
=================
Here is your answer----------
=================
Potetiometer :--
============
It is a device which is used to measure the EMF of cell, comparing the EMF of two cells and to measure the internal resistance of a cell.
☆Principle of
============
Potentiometer :--
=============
Whenever a steady current flows through a wire of uniform area of cross-section and then the potential drop across the wire is directly proportional to the length of the wire.
☆ v is directly proportional to l
v=kl
k = v/l [ Potential gradient]
SI unit of it's is Volt/meter
☆Formula for determining the EMF of cell:--
E= vl'/l
Here, E is EMF of cell
l' is length on potentiometer wire at which galvanometer show null deflection.
l is the length of potentiometer wire
☆ Formula for comparing the EMF of two cells:--
E1 /E2 = l1/ l2
Here E1 = EMF of first cell
E2 = EMF of second cell
l1 = length on potentiometer at which first cell's null deflection is shown
l2 = length on potentiometer at which second cell's null deflection is shown
☆ Formula for determining Internal resistance of cell:--
r = [l1 - l2]/ l2 × R
r = internal resistance
R = Resistance selected by resistance box
Hope it will help you!
==================
Thanks!
=======
Answered by
0
A potentiometer has 3 pins. Two terminals (the blue and green) are connected to a resistive element and the third terminal (the black one) is connected to an adjustable wiper.
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