Physics, asked by ananyadubey2013, 11 months ago

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A Physics Question:-
✨When an electron moves from A to B along an electric field line as shown in figure, the electric field does 3.9×10^(-19) J of work on it. What are the electric potential differences,
(Vb - Va); ( Vc - Va ) ;(Vc - Vb).
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Answers

Answered by rajputkiyaari
2

Hey mate here is the correct answer.....

Equipotential surfaces will be always perpendicular to electric field lines.

The picture of the Question shows the electric field lines and the equipotential surfaces for uniform electric field.

a) Vb - =U/q

=-w/-e

= -[3.4× 10^(-19)]/[-1.60× 10^19]

=2.46V

b) Vc - Va

=Vb - Va

=2.46V

c) Vc -Vb = 0 bcouz B and C are on same equipotential line.

I hope u have understood...

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Answered by CUTESTAR11
0

Explanation:

the electric potential differences...

Vc -Vb = 0.....

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