Question

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Question :

If a = b = c , Prove that a³ + b³ + c³ - 3abc = 0


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Answer 1

Answer:

Hey mate,

if a = b = c

a³ + b³ + c³ - 3abc = a^3 + a^3 + a^3 - 3×a×a×a

a³ + b³ + c³ - 3abc = 3a^3 - 3a^3

a³ + b³ + c³ - 3abc = 0

Hence, Proved

Hope it's helpful

Answer 2

Step-by-step explanation:

given a = b = c,

a³+b³+c³-3abc = a³ + a³ + a³ - 3aaa

= 3a³ - 3a³ = 0

Further a³+b³+c³-3abc = 0.5 (a+b+c){(a-b)²+(b-c)²+(c-a)²}