heyaa !!!!!
Gm everyone ...
solve the question 59 nd 61 respectively !!!!!!
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Answered by
5
Heya.....!!!
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Given in the question
• C = 80%
• H = 20 %
So ,in 100 g of compound these will be
=> H = 20 g
=> C = 80 g
We know that :- Atomic mass of H= 1
Atomic mass of C = 12
Let us take out mole
=> moles of C = 80 / 12 = 6.667 = 20/3
=> moles of H = 20 / 1 = 20
(( multiply both side by 3 ))
=> C => 20
=> H => 60
That is = C20H60
• Empirical Formulae => CH3
• Molecular Formulae => C2H6
============================
Hope It Helps You ☺
_______________
Given in the question
• C = 80%
• H = 20 %
So ,in 100 g of compound these will be
=> H = 20 g
=> C = 80 g
We know that :- Atomic mass of H= 1
Atomic mass of C = 12
Let us take out mole
=> moles of C = 80 / 12 = 6.667 = 20/3
=> moles of H = 20 / 1 = 20
(( multiply both side by 3 ))
=> C => 20
=> H => 60
That is = C20H60
• Empirical Formulae => CH3
• Molecular Formulae => C2H6
============================
Hope It Helps You ☺
Aasthakatheriya1:
thankyou!!!!!
☺☺
Question no. 59 is same
method is same
yaa
acc. to ur ans if they r not Vapour density ya molecular formula we should 100 g
Yes ! :)) we take 100 g
okk
Answered by
3
hey here is your correct option
59 CH4
61 C2H6
hope it helps u
please mark as brainlist
59 CH4
61 C2H6
hope it helps u
please mark as brainlist
give briefly
but no problem
thnks #
welcome and God bless you
definitely u will be a Dr. Aastha
ohh thankyou
nd i also wish want do u want god gives u !!!
thank-you so much
ur welcome!!!!!
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