Question

heyaa...plss give full solution☺☺

Answer 1

let the zeros be a and 7a
Now According to remainder theorem we have
3a^2-8a+2k+1=3×49a^2-56a+2k+1
3a^2-8a=147a^2-56a
147a^2-3a^2-56a+8a=0
144a^2-48a=0
12a^2-4a=0
3a^2-a=0
3a^2=a
3a=1
a=1/3 Ans
7a=7/3 ans
put x=1/3 in equations.
1/3-8/3+2k+1=0
2k=8/3-1/3-1
2k=4/3
k=2/3 ans