Question

Heyaa

Question :

The sum of two digits number is square root of original number. If 63 is subtracted from it, the new number will be equal to the reversed number of it, find the number.

Answer 1

Answer:

Step-by-step explanation:

Let the ones digit be (9-x) and tens digit be x.

Now number = 10(x) + (9-x)= 9x +9.

Interchange of this number will be.

10(9-x) + x= 90 - 9x

According to questions..

9x+9 - 63= 90–9x

18x= 90 + 63 -9

18x= 144

X= 8.

Therefore actual numbers tens place is 8 and ones place is 9–8=1

i.e, 81.

Answer 2

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