heyaaa !!! :-) :-) :-) :-) :-)
help me questions no. 19
will
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hope this helps ..!!
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Hey..
Here is your answer
Given that:
2^a=3^b=6^c
2^a=6^c
raise both sides to power b
2^ab=6^bc..........equation 1
3^b=6^c
raise both sides to power a
3^ab= 6^ac...........equation 2
Multiply 1 and 2
=>2^ab . 3^ab =6^bc . 6^ac
=>6^ab=6^c (a+b)
=> ab=c (a+b)
=> ab/a+b=c
Hence proved that c=ab/a+b
Hope it helps u...
Here is your answer
Given that:
2^a=3^b=6^c
2^a=6^c
raise both sides to power b
2^ab=6^bc..........equation 1
3^b=6^c
raise both sides to power a
3^ab= 6^ac...........equation 2
Multiply 1 and 2
=>2^ab . 3^ab =6^bc . 6^ac
=>6^ab=6^c (a+b)
=> ab=c (a+b)
=> ab/a+b=c
Hence proved that c=ab/a+b
Hope it helps u...
samratadityae:
helle
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