Math, asked by Braɪnlyємρєяσя, 3 months ago

HEYE,






\huge \fbox \red{❥ Question}


In the figure, AB and CD are two diameters of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. If OA = 7 cm, find the area of the shaded region.​


Anonymous: hmm
Anonymous: my Biography... ...xd
Anonymous: read it
Anonymous: bio
aarivukkarasu: hi guys
aarivukkarasu: good afternoon
Anonymous: Good afternoon
aarivukkarasu: good afternoon
Anonymous: um

Answers

Answered by Anonymous
5

Answer:

HEYE,

\huge \fbox \red{❥ Question}

In the figure, AB and CD are two diameters of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. If OA = 7 cm, find the area of the shaded region.

Step-by-step explanation:

\huge{\boxed{\mathfrak{\overbrace{\underbrace{\fcolorbox{r}{red}{✯Answer}}}}}}

ATTACHED ABOVE

\huge\red{sunday}

_______*THE END*_______

Attachments:

Anonymous: if u didn't forget me than why don't u talk
aarivukkarasu: hi
Anonymous: hello
aarivukkarasu: can I come in
Anonymous: yeah of course
aarivukkarasu: how are you
Anonymous: Fine
Anonymous: u?
aarivukkarasu: good
Anonymous: hmm
Answered by aarivukkarasu
8

Step-by-step explanation:

Radius of bigger circle r1 = OA =7

Radius of smaller circle R2 = r1/2 = 7/2

Area of the bigger circle CC1 = π r1 ^2

22/7 × 7 × 7

=154cm^2

Area of the semicircle = 154/ 2 cm^2

=77cm^2

Area of the smaller circle C2 = πr 2^2

22/7 × 7/2 ×7/2

= 77/2

Area of the unshaded triangle △ABC= 1/2 × AB ×OC

1/2 ×14×7

=49cm ^2

∴ Area of the shaded portion =Area of the smaller circle +(Area of semicircle -Area of the triangle △ABC)

= 77/2 + (77-49) =66.5cm^2

hope it helps you

good night


Anonymous: hi monika
aarivukkarasu: hi mayur
Anonymous: read my
Anonymous: bio
Anonymous: hahaha
Anonymous: Mayuresh
Anonymous: aapka bio mast hai❤
Similar questions