Question

HeyMate☺️
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1⃣Using Euclid's Division Algorithms,
Find HCF of
270,405 and 315
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Answer 1

first, we have to find the HCF of first two numbers.

let's consider 270 and 405.

we know that a = bq + r, 0 ≤ r < b (a = dividend, b = divisor, q = quotient and r = remainder)

using division method we get,

➡ 405 = 270 × 1 + 135

➡ 270 = 135 × 2 + 0

when remainder comes 0, the divisor is the HCF.

hence, remainder of 270 and 405 is 135.

now, find HCF of 135 and 315.

we get,

➡ 315 = 135 × 2 + 45

➡ 135 = 45 × 3 + 0

therefore, 45 is the HCF OF 270, 405 and 315.