Question

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Question :- A truck starts from rest and rolls down a hill with constant acceleration .It travels a distance of 400m in 20s .Find its acceleration .Find the force acting on it if its mass is 7 metric tonnes.

Answer 1

Answer:

f=m*a

=7000kg *20m per second = acceleration

f=140000kgmpersec

140000N

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Answer 2

$\mathfrak{Answer}$ :-

Step-by-step explanation:

Given ,

Truck starts from rest

Initial $\bold{Velocity}$ (u)= 0m/s

$\huge\bold{Distance}$covered(s) = 400m

$\huge\bold{Time}$ taken (t)=20 seconds

Mass = 7 metric tonnes = 7 * 1000 = 7000kg

Final velocity (v) = ?

Acceleration (a) = ?

Force (F) = ?

Using equation of motion ,

S = ut + 1/2 at^2 , acceleration is ,

400 m = 0+1/2(a)(20)^2

400*2 = a*400

a = 2 m/s^2

Using equation , v = u +at

Final velocity (v) = 0+2*2 = $\boxed{4m/s}$

Since ,

Force = Mass (m) * acceleration(a)

F = 7000 * 2

Force = $\boxed{14000N}$