Question

heyy...
.
.
a force act on a body of mass 50 kg,for 10 second.when force stop acting on a body, the body covers 80 m in the next 10 second.what is the magnitude of the force?

if u dont know do not answer..

Answer 1

$<I>$☞HEYA MATE☜

⚫
a force act on a body of mass 50 kg,for 10 second.when force stop acting on a body, the body covers 80 m in the next 10 second.what is the magnitude of the force?

★ ANSWERR :

ANSWER:

m=10kg.
F=ma.
Using v-u=at.
t=10s.
v=at.(considering the body starts from rest).
After 10s ,the force ceases and the body starts moving with velocity v.It covers 50m in 5s.
s=vt=50m.
s=(10a)5=50
a=1m/s² .
F=10×1N.
F=10N.

❣️hope it helps uh ❣️

Answer 2

Hope this will help u... :-)