Question

Heyy frnds need ur help !!

challenge for u all $$!!!!!


Can anyone solve this ?????


All the best !!

explain in easy language ☺!!

Answer 1

Let The Area Of Full Disk be M

So, M = π(2R)²

M = 4πR²

And Area of small Disk be m

m = πR²

So On cutting m from M the Area left will be,

M1 = M - m

M1 = 3πR²

Now The Centre Of Mass is At C2 the moment of masses about CM is zero, therefore moment of cutout disc and Left disc about C is zero.

So m*CC1 + M1*CC2 = 0

m*R + M1*CC2 = 0

(3πR²).CC2 = πR³

CC2 = πR³/3πR²

CC2 = R/3

So the Distance Moved Will Be R/3