Question

Heyy guys...
if position Vs time equation of particle is y=6t^2-2t+10,where y is in metre and t in sec. find:
a)initial position of particle
b) velocity after 3 sec
c) initial velocity of particle
d) acceleration after 2 sec
e) initial acceleration of particle
f) velocity of particle when acceleration is zero.
Plzz answer ASAP.. ​

Answer 1

Answer:

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