Heyy guys need ur help!!
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The figure shows the situation:
here Ng is the reaction of ground, Nw is the reaction of the wall and f is the force due to friction. In this condition when ladder is at rest all forces are balanced so
for horizontal forces,
Nw=f
for vertical forces ,
Ng=20+50N
so ,
Ng=70 N
also torques due to these forces are in equilibrium.
therefore,...
torques in anti clock wise direction=torques in clock wise direction.....
or...
τ(wall)=τ(ladder) + τ(man)
(all torques are taken about ground poin A)
Nwsin60∘·6=20×3sin30+50×4sin30∘Nw×3√2×6
=60×12+200×12Nw
=26063√Nw
=25.01 N
HOPE IT HELPS
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Heyyyy here is your answer in attachment
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