Question

heyy guys urgent help​

Answer 1

initial velocity u= 10m/s

acceleration is 5 m/s²

$s = ut + \frac{1}{2} a {t}^{2} \\ = 10 \times 5 + \frac{1}{2} a {t}^{2} \\ 50 + \frac{1}{2 } 5 \times {5}^{2} \\ 50 + \frac{1}{2} \times 125 \\ 50 + 62.5 \\ = 112.5m \\ \\ hope \: it \: helps \: you$

Answer 2

Step-by-step explanation:

Hey mate

here is your answer

v = final velocity, u= initial velocity, a = acceleration and s = distance

v = u + at

v = 10ms^-1 + 5m/s²×5s

v = 10m/s+25m/s

v = 35m/s

now that we obtained the final velocity

s = ut + 1/2at²

s = 10m/s×5s+1/2×5m/s²×5s×5s

s= 50m + 1/2×125m

s = 50m + 62.5m

s = 112.5m

i hope you have a nice day