Question

Heyy Guyss..
Solve the above sum..​

Answer 1

Hey mate,

Given,

U = 75 km/s

V = 120 km/s

t = 6 sec

We have,

Equation of motion,

V = U + at

120 = 75 + 6a

So,

Acceleration comes out to be = 7.5 km/s^2

Again, by equation of motion,

V^2 = U^2 + 2*a*s

Now plug in the values to find,

S = 585 km

Assumptions :-

Let the rocket stop after 6 sec

The velocity remains constant for 120km/s

After 6 sec rocket travels for 4 more seconds,

So total distance for 4 sec = 4*120

= 480 km

Total distance in 10 sec = 585 + 480

= 1065 km

Hope this helps you out!

Answer 2

$\underline{\underline{\huge\mathfrak{Answer :}}}$

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$<b><I>Given,$

» Initial Velocity (u) = 75kms^-1

» Final Velocity (v) = 120km^-1

» Duration (rocket motors) = 6 seconds

i] Average Acceleration = ?

From First Equation of Motion

$v = u + at \\ 120 = 75 \: + \: a \: \times 6 \\ 120 - 75 = a \: \times 6 \\ 45 \ \div \: 6 = a \\ 7.5 = a$

Hence, Acceleration = 7.5ms^-2

ii] Distance Travelled = ?

From Third Equation of Motion

$v { \: }^{2} = \: u { \: }^{2} + 2as \ \\ 120 { \: }^{2} = 75 { \: }^{2} + 2 \times 7.5 \times s \\ 14400 - 5625 = 15 \times s \\ 8775 \div 15 = s \\ 585 = s$

Distance = 585 meters

Few Assumptions :

• The Rockets Were Fired For a Brief Period Of Time. So, After 6 seconds They Stop.

• Due To Its Property of Inertia And Being in Space (no Air Resistance since Space is a Vacuum), The Body Continued to Travel at a Constant Velocity of 120kms-1

Thus, Given Time Period is 10 seconds and Rockets Were In Action for Only 6 seconds.

The Spacecraft Will Travel for About 4 More Seconds covering a Distance of :

Distance = Velocity × time = 120 × 4 = 480 km.

Henceforth, The Total Distance Traveled = 585 + 480 = 1065 meters.

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P.S. - I WAS GETTING BORED : |