heyy guyzz....
plss help me....
if 3b = a + c where a, b, c are real numbers, then the line Ax + By + C is equal to zero always passes through a fixed point whose coordinates are:
1-(1, -3)
2-(-1, 3)
3-(-1, -3)
4-(1 ,3)
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Given:
The expression 3b = a + c
Also given the line equation ax + by + c = 0
To Find:
The coordinates of the fixed point through which the line Ax + By + C is equal to zero always passes.
Solution:
Given 3b = a + c
- This can be written as a -3b + c = 0 - (1)
Also line equation:
- ax + by + c = 0 - (2)
Since right hand side of both the equation is zero, lets equate them.
- ax + by + c = a - 3b + c
Values of a, b and c are fixed . Only x and y are variables.
Hence we can infer that,
- x = 1 and y = -3.
Therefore the line ax + by + c= 0 always passes through the point (1,-3).
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