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If a3 =8 and a6=17 , find a14 ??
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Step-by-step explanation:
Hey Ladle!
Jay bholanath _/\_
Third term = a3 = a+2d = 8
Sixth term = a6 = a+5d = 17
a14 = ?
======================
a + 2d = 8 ----(1)
a + 5d = 17----(2)
Subtracting (2) from (1) we get,
-3d = - 9
d = 3
Substituting the value of d in equation (1) we get
a + 2d = 8
a + 2(3) = 8
a + 6 = 8
a = 2
==========================
Therefore,
a14 = a + 13d
= 2 + 13(3)
a14 = 41
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