Question

Heyy.
Please answer this question!!

Answer 1

$\tan( \alpha ) = \frac{h}{a}$
$\tan(90 - \alpha ) = \frac{h}{b} \\ \cot( \alpha ) = \frac{h}{b} \\ \tan( \alpha ) = \frac{b}{h}$
now
$\frac{h}{a} = \frac{b}{h} \\ {h}^{2} = ab \\ h = \sqrt{ab}$

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