heyy Sameer what about value of B
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Answer:
if 4bc is divisible by 15 then your it was divisible by 3 and 5
c=5
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1
Answer:
4BC is divisible by 15 so the number must divisible by 5&3
so a number to divisible by 5 the number must end with 5 or 0
so C= 5 or 0
a number to divisible by 3 the sum of numbers must be a multiple of 3
so 4+B+5 or 4+B+0 are divisible by 3
now from second equation
4+B+0= 4+B
now B might be 2,5,or8
- 4+2=6
- 4+5=9
- 4+8=12
- 6,9,12are divisible by 3
now we take the first equation 4+B+5
B+9
- 3+9=12
- 6+9=15
- 9+9=18
here value of B might be 3,6,9
from 2 cases B might be 6,9 and C might be 0,5
so we get 4 numbers
- 460
- 465
- 490
- 495
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