Question

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a gas is enclosed in rectangular vessel 20 × 10^ 23 molecules of the gas strike a wall of vessel normaly per second. with the velocity to 50 M/ s and rebound with the same speed in opposite direction what is the force exerted by the gas on the wall if the mass of each molecule is 5×10^-23

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Answer 1

As 20× 10^23 molecules strike per second

and mass of each is 5× 10^ -23

So total mass strike per second is

20× 10^ 23 ×5 × 10^-23

100 gm = 100/1000 = 0.1 kg/s

As change in momentum would doubled

As force = dp/dt

So force would get doubled

= 2× 0.1 × 50= 10 N