Question

heyyaa

Distance between two points (8,- 4) and (0, a) is 10. All the values are in the same unit of length. Find positive value of a.

pls answer this

tysm❤⭐​

Answer 1

Answer:

Step-by-step explanation:

Distance b/w two points is equal to saqure root of

(x2-x1)^2 +(y2-y1)^2

Here x1=8, x2=0, y1=-4, y2=a

Distance =10

So

100=(0–8)^2+(a+4)^2

100=64+a^2+16+8a

a^2+8a-20=0

a^2+10a-2a-20=0

a(a+10)-2(a+10)=0

(a+10)(a-2)=0

Hence a=2,-10

hope this will help u dear ##

Answer 2

Answer:

Value of  a is 2.

Step-by-step explanation:

Given: Distance between Point A ( 8 , -4 )  and Point b ( 0 , a ) = 10 unit

To find: Value of a

We know that Distance between two point is given as follows:

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A and B =   10

$\sqrt{(0-8)^2+(a-(-4))^2}=10$

$\sqrt{(-8)^2+(a+4)^2}=10$

$\sqrt{64+(a+4)^2}=10$

Squaring both sides , we get

64 + ( a + 4 )² = 100

( a + 4 )² = 100 - 64

( a + 4 )² = 36

a + 4 = ±6

a + 4 = 6     or    a + 4 = -6

a = 6 - 4     or    a = -6 - 4

a = 2          or    a = -10

Since, Value of a is positive. we choose a = 2

Therefore, Value of  a is 2