Question

heyyy mates pls answer meee ​

Answer 1

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The moment of inertia of four circular plates = 4 x 1/2 M'R²

Where M' is the mass of each square plate

The moment of intertia of square plate about Z - axis = 1/6 (4R)²

= 8/3 MR²

M.I of remaining portion = 8/3 MR² - 2MR²

= (8/3M - 2M') R²

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