Question

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radius of 3rd orbit of Li2+........ ​

Answer 1

$\huge\bold\red{ANSWER:-}$

The radius of the orbital os Li2+ ion in third orbital

we have a formula :-

r=0.529*n^2/Z ( if we use this formula we get the answer in angstorm )

here r= radius

n= orbit number

Z= atomic number

r = 0.529*3^2/3

r=0.529*9/3

r=0.529*3=1.587 angstorm

to convert angstorm to meter multiply by 10^-10

 therefore 1.587angstorm= 1.587*10^-10m

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Answer 2

Answer -

1.58Å

Explanation-

Atomic no. of lithium = 3

radius of 3rd orbit = ?

$raidus \: of \: n \: orbit \: = 0.529 \times \frac{ {n}^{2} }{z}$

Radius of 3rd orbit =

==> $0.529 \times \frac{ {3}^{2} }{3}$

==> 1.58Å

hence, radius of 3rd orbit is 1.58Å