Question

Heyyyaaaaa.... Try this...... ​

Answer 1

Answer:

late at an instant current through the circuit is I then,

IR+£=E

£=E-IR

therefore graph between I and £will be straight line having negative slope and having positive Intercept

Answer 2

Hey mate

here's the answer

IR+£=E

£=E-IR

Thus the graph between I and £ have straight line having negative slope and having positive Intercept.

Hope it helps ❤