Chemistry, asked by tarushatarusha107, 1 day ago

Heyyyy ... Answer this please

The change in energy on freezing 1.0 kg of liquid water at 0°C and atm is (Given energy of 1 fusion of ice = 6.03 kJ mol-l at 0°C) (a) 235 kJ per kg (b) 450 kJ per kg (c) -335 kJ per kg (d) -235 kJ per kg​

Answers

Answered by divakarvajja286
0

Answer:

c option

Explanation:

AE=n.e

-1000/18×6.03

=-335 Kj per kg

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