Heyyyy ... Answer this please
The change in energy on freezing 1.0 kg of liquid water at 0°C and atm is (Given energy of 1 fusion of ice = 6.03 kJ mol-l at 0°C) (a) 235 kJ per kg (b) 450 kJ per kg (c) -335 kJ per kg (d) -235 kJ per kg
Answers
Answered by
0
Answer:
c option
Explanation:
AE=n.e
-1000/18×6.03
=-335 Kj per kg
Attachments:
Similar questions