Question

heyyyy friends

Tell me differentiation of 2x sinx

Answer 1

2x cosx + 2sinx is the answer

Answer 2

HEY MISS ...

HERE'S THE ANSWER.


_______________________


▶️ We'll be using product rule in this i.e

=> ( u . v )' = u' . v + v' . u

⏺️Here , x is like u and sin x is v

⏺️ Now differentiating both sides w.r.t. x

=> 2 [ ( x )' . sin x + ( sin x )' x ]

=. 2 [ 1 . sin x + cos x . x ] // ( sin x )' = cos x

=> 2 sin x + 2 x cos x

▶️ If u have any doubt in calculus ..just ping me..


HOPE HELPED..


GOOD NIGHT..


:-)