Math, asked by Anonymous, 10 months ago

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plsssss answer this
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Answered by Anonymous
1

Step-by-step explanation:

sin^6Ф - cos^6Ф

==> (sin²Ф)³ - (cos²Ф)³

use the formula,

a³ - b³ = (a - b)(a² + b² + ab )

==> (sin²Ф - cos²Ф)(sin⁴Ф+ cos⁴Ф+ sin²Ф.cos²Ф)

==> -(cos²Ф- sin²Ф){(sin²Ф + cos²Ф)² - 2sin²Ф.cos²Ф + sin²Ф.cos²Ф}

==> - cos2Ф.{ 1 - 1/4(2sinФ.cosФ)²}

==> -cos2Ф(4 - sin²2Ф)/4

Answered by Shrutirawat2004
0

Answer:

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