Question

Hfc and Lcm of 12,15,and 24
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Answer 1

Let's See

By FACTORISATION METHOD,

12 = 2× 2×3

15 = 3 × 5

24 = 2 ×2× 2× 3

Required LCM = 3 × 2 × 2× 2 × 5 = 180

Required HCF = 3

Note:- i) First break all no. in prime factors

ii) Choose the no. , common in all & write once in Required LCM & Required HCF.

iii) Next choose the no. present(common) in any two terms & write once in Required LCM but in Required HCF.

iv) At last write all left no. in Required LCM

v) In Required LCM, multiply all no. to the answer. )

Hope you understood.

Enjoy Maths!!

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